Probleme de informatica - enunturi si rezolvari

Se citeste un numar natural n (n<=100). Construiti si afisati o matrice patratica cu n linii si n coloane dupa modelele de mai jos.
Pentru n=7 se obtine matricea:
0 1 2 3 2 1 0
1 0 4 5 4 0 1
2 4 0 6 0 4 2
3 5 6 0 6 5 3
2 4 0 6 0 4 2
1 0 4 5 4 0 1
0 1 2 3 2 1 0
Pentru n=8 se obtine matricea:
0 1 2 3 3 2 1 0
1 0 4 5 5 4 0 1
2 4 0 6 6 0 4 2
3 5 6 0 0 6 5 3
3 5 6 0 0 6 5 3
2 4 0 6 6 0 4 2
1 0 4 5 5 4 0 1
0 1 2 3 3 2 1 0

#include <iostream>

using namespace std;
int A[101][101];
int main()
{
    int n,x=1;
    cin>>n;
    for(int i=1;i<=n/2;i++)
        for(int j=i+1;i+j<n+1;j++)
        {
            if(j<=(n+1)/2) A[i][j]=x;
            else A[i][j]=A[i][n+1-j];
            A[j][i]=A[n+1-j][n+1-i]=A[n+1-i][n+1-j]=A[i][j];
            if(j<=(n+1)/2) x++;
        }
    for(int i=1;i<=n;i++)
    {
        for(int j=1;j<=n;j++)
            cout<<A[i][j]<<" ";
        cout<<endl;
    }
    return 0;
}

sau

#include <iostream>

using namespace std;
int A[101][101];
int main()
{
    int n,x=1;
    cin>>n;
    for(int i=1;i<=n/2;i++)
        for(int j=i+1;j<=(n+1)/2;j++)
        {
            A[i][j]=x;
            A[i][n+1-j]=x;
            A[n+1-j][i]=A[j][n+1-i]=A[n+1-i][j]=A[i][n+1-j];
            A[j][i]=A[n+1-j][n+1-i]=A[n+1-i][n+1-j]=A[i][j];
            x++;
        }
    for(int i=1;i<=n;i++)
    {
        for(int j=1;j<=n;j++)
            cout<<A[i][j]<<" ";
        cout<<endl;
    }
    return 0;
}

21 nov 2024

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